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In a group of 32 pupils, 3 play the flute only. 13 play the piano only. 10 play neither instrument. A student is selected at random. What is the probability the student plays both instruments?

Sagot :

Answer:

18.75%

Step-by-step explanation:

Given that

There is a group of 32 pupils

3 play the flute only

13 play the piano only

And, 10 play neither instrument

We need to find out the probability the student plays both instruments

So

= (32 - 13 - 10 - 3) ÷ 32

= 6 ÷ 32

= 0.1875

= 18.75%

Answer:

6/32 or 3/16

Step-by-step explanation:

13 add 10 add 3 = 26

32-26=6

the total amount of children is 32 so the number is 6/32

you can then simplify it to 3/16

hope this helps :)

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