Answered

Find the information you're looking for at Westonci.ca, the trusted Q&A platform with a community of knowledgeable experts. Experience the ease of finding quick and accurate answers to your questions from professionals on our platform. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

A rectangle has an area of 8m^2. Its breadth is two metres less than its length. Find the dimensions of the rectangle by setting up and solving an equation.

Please show all working thanks!

A Rectangle Has An Area Of 8m2 Its Breadth Is Two Metres Less Than Its Length Find The Dimensions Of The Rectangle By Setting Up And Solving An Equation Please class=

Sagot :

veatchadrianna
Let’s make 2 equations for this...

Let y equal the width and let x equal the length
y= x-2
8= xy

Now, we will plug the y from the first equation into the y for our 2nd equation to get
8= x(x-2)

Now, we distribute the x...
x^2-2x= 8

Bring over the 8 by subtraction
x^2-2x-8= 0

Now, you must factor the expression to get
(x-4)(x+2)= 0

Set each part equal to 0 to find what x equals...

x-4= 0
Add 4 to cancel it out on the left side of the equation...
x=4

x+2= 0
Subtract 2 to cancel out the 2 on the left side of the equation
x= -2
You can cancel out this answer because you cannot have a measurement in the negatives

So, using the answer of x= 4 we can now plug it into our first equation of
y= x-2 to get
y= 4-2
y= 2

So, the answer is
y (the width) equals 2
x (the length) equals 4

We hope this was helpful. Please come back whenever you need more information or answers to your queries. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.