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Sagot :
Answer:
Explanation:
1 ) angular frequency ω = √ ( k / m )
=√ ( 170 / 50 )
= 1.844 rad /s
2πn = 1.844 where n is frequency of oscillation
n = 1.844 / (2 x 3.14 )
= .294 per sec
= .294 x 60 = 18 approx. per minute .
Velocity just after collision of composite mass ( using law of conservation of momentum )
= 25 x 2.8 / 50
v = 1.4 m/s
If new amplitude be A
1/2 k A² = 1/2 m v²
m = 25 + 25 = 50 kg
170 x A² = 50 x 1.4²
A = 0.76 m
3 ) period of oscillation = 1 /n
= 1 / .294
= 3.4 s
4 ) It will take complete one period of oscillation ie 3.4 s to come to its original position.
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