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Sagot :
Answer:
The integer can be -1 or 5.
Step-by-step explanation:
Let an integer is x.
ATQ,
The square of an integer is 5 more than 4 times the integer.
[tex]x^2=5+4x[/tex]
or
[tex]x^2-5-4x=0\\\\x^2-4x-5=0[/tex]
It is a quadratic equation. Using middle term splitting,
[tex]x^2-5x+x-5=0\\\\x(x-5)+1(x-5)=0\\\\(x+1)(x-5)=0\\\\x=-1,5[/tex]
So, the integer can be -1 or 5.
If the square of an integer is 5 more than 4 times the integer, the integers are -1 and 5
Let the unkown integer be "x"
The square of an integer is expressed as x^2
5 more than 4 times the integer is expressed as [tex]4x +5[/tex]
Equate both expressions to have:
[tex]x^2 = 4x + 5\\[/tex]
Equate to zero and factorize:
x^2 - 4x - 5 = 0
x^2 - 5x + x - 5 = 0
x(x - 5) + 1(x - 5) = 0
(x + 1)(x - 5) = 0
x = -1 and 5
Hence the integers are -1 and 5
Leearn more here: https://brainly.com/question/13805464
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