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Given: AC Bisects Statements reasons

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Sagot :

msm555

Answer:

Answer:

Solution given;

<BCA=<ACD

<ABC=<ADC

now

In traingle ABC & ∆ ACD

AC=AC[common base]

<BCA=<ACD[bisector bisect it]

<ABC=<ADC[Given]

∆ABC is congruent to ∆ ACD by S.A.A. axiom

AB is congruent to AD.

[ corresponding sides of a congruent triangle are equal]

Hence proved.

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