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Calculate the kinetic energy of a 790-kg roller coaster traveling at a velocity of 20.7 m/s.

Sagot :

HenryDavid04

Answer:

The answer is 169253.55 joules

Space

Answer:

[tex]\displaystyle KE = 169254 \ J[/tex]

General Formulas and Concepts:

Energy

Kinetic Energy Formula: [tex]\displaystyle KE = \frac{1}{2}mv^2[/tex]

  • KE is kinetic energy (in J)
  • m is mass (in kg)
  • v is velocity (in m/s)

Explanation:

Step 1: Define

[Given] m = 790 kg

[Given] v = 20.7 m/s

Step 2: Solve

  1. Substitute in variables [Kinetic Energy Formula]:                                           [tex]\displaystyle KE = \frac{1}{2}(790 \ kg)(20.7 \ m/s)^2[/tex]
  2. [KE] Evaluate exponents:                                                                                  [tex]\displaystyle KE = \frac{1}{2}(790 \ kg)(428.49 \ m^2/s^2)[/tex]
  3. [KE] Multiply:                                                                                                     [tex]\displaystyle KE = (395 \ kg)(428.49 \ m^2/s^2)[/tex]
  4. [KE] Multiply:                                                                                                     [tex]\displaystyle KE = 169254 \ J[/tex]
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