Answered

Welcome to Westonci.ca, where your questions are met with accurate answers from a community of experts and enthusiasts. Explore a wealth of knowledge from professionals across different disciplines on our comprehensive platform. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

Calculate the kinetic energy of a 790-kg roller coaster traveling at a velocity of 20.7 m/s.

Sagot :

HenryDavid04

Answer:

The answer is 169253.55 joules

Space

Answer:

[tex]\displaystyle KE = 169254 \ J[/tex]

General Formulas and Concepts:

Energy

Kinetic Energy Formula: [tex]\displaystyle KE = \frac{1}{2}mv^2[/tex]

  • KE is kinetic energy (in J)
  • m is mass (in kg)
  • v is velocity (in m/s)

Explanation:

Step 1: Define

[Given] m = 790 kg

[Given] v = 20.7 m/s

Step 2: Solve

  1. Substitute in variables [Kinetic Energy Formula]:                                           [tex]\displaystyle KE = \frac{1}{2}(790 \ kg)(20.7 \ m/s)^2[/tex]
  2. [KE] Evaluate exponents:                                                                                  [tex]\displaystyle KE = \frac{1}{2}(790 \ kg)(428.49 \ m^2/s^2)[/tex]
  3. [KE] Multiply:                                                                                                     [tex]\displaystyle KE = (395 \ kg)(428.49 \ m^2/s^2)[/tex]
  4. [KE] Multiply:                                                                                                     [tex]\displaystyle KE = 169254 \ J[/tex]
Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.