Answered

At Westonci.ca, we connect you with the answers you need, thanks to our active and informed community. Explore thousands of questions and answers from a knowledgeable community of experts on our user-friendly platform. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

Calculate the kinetic energy of a 790-kg roller coaster traveling at a velocity of 20.7 m/s.

Sagot :

HenryDavid04

Answer:

The answer is 169253.55 joules

Space

Answer:

[tex]\displaystyle KE = 169254 \ J[/tex]

General Formulas and Concepts:

Energy

Kinetic Energy Formula: [tex]\displaystyle KE = \frac{1}{2}mv^2[/tex]

  • KE is kinetic energy (in J)
  • m is mass (in kg)
  • v is velocity (in m/s)

Explanation:

Step 1: Define

[Given] m = 790 kg

[Given] v = 20.7 m/s

Step 2: Solve

  1. Substitute in variables [Kinetic Energy Formula]:                                           [tex]\displaystyle KE = \frac{1}{2}(790 \ kg)(20.7 \ m/s)^2[/tex]
  2. [KE] Evaluate exponents:                                                                                  [tex]\displaystyle KE = \frac{1}{2}(790 \ kg)(428.49 \ m^2/s^2)[/tex]
  3. [KE] Multiply:                                                                                                     [tex]\displaystyle KE = (395 \ kg)(428.49 \ m^2/s^2)[/tex]
  4. [KE] Multiply:                                                                                                     [tex]\displaystyle KE = 169254 \ J[/tex]
Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.