Answered

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solve log2+log16/15+12log25/24+7log8
[tex] log_{10}2+ log_{10} \frac{16}{15} + 12 log_{10} \frac{25}{24} + 7 log_{10} \frac{81}{80 = 1[/tex]
1/80=1​

Sagot :

kaytlynn294

Answer:

the answer is -non existent

Step-by-step explanation:

there is no answer to this problem

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