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Sagot :
Answer:
Explanation:
pH = -log{H+]
{H+} = 10^(-pH)
pOH = 14 - pH
{OH-} = 10^(-pOH)
pH 2.90 (the approximate pH of lemon juice
{H+} = 10^(-2.9)
pOH = 14 - 2.9 = 11.1
{OH-} = 10^(-pOH) = 10^(-11.1)
pH 3.86 (the approximate pH of sauerkraut)
{H+} = 10^(-3.86)
pOH = 14 - 3.86 = 10.14
{OH-} = 10^(-pOH) = 10^(-10.14)
pH 10.81 (the approximate pH of milk of magnesia)
{H+} = 10^(-10.81)
pOH = 14 - 10.81 = 3.19
{OH-} = 10^(-pOH) = 10^(-3.19)
pH 4.11 (the approximate pH of orange juice)
{H+} = 10^(-4.11)
pOH = 14 - 4.11 = 9.89
{OH-} = 10^(-pOH) = 10^(-9.89)
pH 11.61 (the approximate pH of household ammonia)
{H+} = 10^(-11.61)
pOH = 14 - 11.61 = 2.39
{OH-} = 10^(-pOH) = 10^(-2.39)
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