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Sagot :
Answer:
12
Step-by-step explanation:
Assuming the diagram is thesame as the one attached,
From the diagram,
Triangle ABC is similar to Triangle DEC
ΔABC is similar to ΔDEC
Note: In similar triangle, ratio of corresponding sides are equal
Therefore,
line(AB) /line(DE) = line(BC)/line(EC).................... Equation 1
Given: AB = 20, BC = 15, EC = BC-BE = (15-6) = 9
Substitute these values into equation 1 and solve for Line DE
20/DE = 15/9
DE = (20×9)/15
DE = 12.
Hence line DE = 12.
Answer:
[tex]DE=12[/tex]
Step-by-step explanation:
From the question we are told that:
[tex]AB=20\\\\BC=15\\\\BE =6[/tex]
Generally the equation for the similar triangles is mathematically given by
[tex]\frac{AB}{BC} =\frac{DE}{EC}[/tex]
Where
[tex]EC = BC - BE \\\\EC= 15-6 \\\\EC= 9[/tex]
Therefore
[tex]\frac{20}{15} =\frac{DE}{9}[/tex]
[tex]\frac{20*9}{15} =DE[/tex]
[tex]DE=12[/tex]
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