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Rectangle ABCDABCDA, B, C, D is graphed in the coordinate plane. The following are the vertices of the rectangle: A(-2, 2)A(−2,2)A, left parenthesis, minus, 2, comma, 2, right parenthesis, B(6, 2)B(6,2)B, left parenthesis, 6, comma, 2, right parenthesis, C(6, 3)C(6,3)C, left parenthesis, 6, comma, 3, right parenthesis, and D(-2, 3)D(−2,3)D, left parenthesis, minus, 2, comma, 3, right parenthesis.
What is the area of rectangle ABCDABCDA, B, C, D? Please Help

Sagot :

Answer:

Step-by-step explanation:

The rectangle ABCD has vertices A(-2,2), B(6,2), C(6,3) and D(-2,3).

Now, length of side AB = [6 - (- 2)] = 8 units.

{Since the line AB is parallel to the x-axis, so the length of the segment AB will be the difference between the x-coordinates of the points A and B}

Again, line BC is parallel to y-axis and hence the length BC = (3 - 2) = 1 units.

Therefore, the area of the rectangle ABCD will be (8 × 1) = 8 sq. units. (Answer)

COOLDUDATS

Answer:

8 Square Units

Step-by-step explanation:

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