Answered

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A hydraulic system is lifting a 11760 N car using a cylinder with an area of 0.25 m
squared. What force is applied to the small cylinder if it has an area of 0.0125 m
squared?

Sagot :

Answer:

F₂ = 588 N

Explanation:

Given that,

Force, F₁ = 11760 N

Area of the cylinder, A₁ = 0.25 m²

Force on small cylinder, F₂ = ?

The area of the small cylinder, A₂ = 0.0125 m²

We know that, according to Pascal's law,

[tex]P_1=P_2\\\\\dfrac{F_1}{A_1}=\dfrac{F_2}{A_2}\\\\F_2=\dfrac{F_1A_2}{A_1}\\\\F_2=\dfrac{11760 \times0.0125 }{0.25 }\\\\F_2=588\ N[/tex]

So, the force on the small cylinder is equal to 588 N.

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