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Sagot :
Answer:
F₂ = 588 N
Explanation:
Given that,
Force, F₁ = 11760 N
Area of the cylinder, A₁ = 0.25 m²
Force on small cylinder, F₂ = ?
The area of the small cylinder, A₂ = 0.0125 m²
We know that, according to Pascal's law,
[tex]P_1=P_2\\\\\dfrac{F_1}{A_1}=\dfrac{F_2}{A_2}\\\\F_2=\dfrac{F_1A_2}{A_1}\\\\F_2=\dfrac{11760 \times0.0125 }{0.25 }\\\\F_2=588\ N[/tex]
So, the force on the small cylinder is equal to 588 N.
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