Answered

Westonci.ca is the premier destination for reliable answers to your questions, brought to you by a community of experts. Get immediate and reliable solutions to your questions from a community of experienced experts on our Q&A platform. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

A hydraulic system is lifting a 11760 N car using a cylinder with an area of 0.25 m
squared. What force is applied to the small cylinder if it has an area of 0.0125 m
squared?


Sagot :

Answer:

F₂ = 588 N

Explanation:

Given that,

Force, F₁ = 11760 N

Area of the cylinder, A₁ = 0.25 m²

Force on small cylinder, F₂ = ?

The area of the small cylinder, A₂ = 0.0125 m²

We know that, according to Pascal's law,

[tex]P_1=P_2\\\\\dfrac{F_1}{A_1}=\dfrac{F_2}{A_2}\\\\F_2=\dfrac{F_1A_2}{A_1}\\\\F_2=\dfrac{11760 \times0.0125 }{0.25 }\\\\F_2=588\ N[/tex]

So, the force on the small cylinder is equal to 588 N.

Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.