nevaehwilsonhuerta
Answered

Welcome to Westonci.ca, the ultimate question and answer platform. Get expert answers to your questions quickly and accurately. Explore a wealth of knowledge from professionals across different disciplines on our comprehensive platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

a student standing in an elevator at rest notices that her pendulum has a frequency of oscillation of 0.5 Hz. a. what is the length of the pendulum's string? b. the elevator starts to accelerate upwards. what effect will this have on the oscillation? explain.​

Sagot :

Explanation:

Given that,

The frequency of oscillation, f = 0.5 Hz

(a) Let the length of the pendulum string is l. So,

[tex]T=2\pi \sqrt{\dfrac{l}{g}}[/tex]

T is time period, T = 1/f

So,

[tex]l=\dfrac{(\dfrac{1}{f})^2g}{4\pi ^2}\\\\l=\dfrac{(\dfrac{1}{0.5})^2\times 9.8}{4\times 3.14 ^2}\\\\l=0.993\ m[/tex]

(b) When the elevator starts to accelerate upwards, new acceleration is a+g.  If accelerating upward, the value of g has increased, because of inertia. So it will feel heavier and the period will decrease.

Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.