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Problem: A tire on a car has an air pressure of 32 PSI when it is 62 Foutside. Overnight the temperature drops to 40° F. What happens to the pressure in the tire overnight?

Sagot :

Question: A tire on a car has an air pressure of 32 PSI when it is 62 ° F. Overnight the temperature drops to 40° F. What happens to the pressure in the tire overnight

Answer:

30.65 psi

Explanation:

Applying,

P/T = P'/T'..................... Equation 1

Where P = Initial pressure, T = Initial Temperature, P' = Final pressure, T'= Final Temperature.

make P' the subject of the equation

P' = PT'/T................. Equation 2

From the question,

Given: P = 32 psi, T = 62 ° F = 289.817 K, T' = 40 ° F = 277.594 K

Substitute these values into equation 2

P' = (32×277.594)/(289.817)

P' = 30.65 psi

Hence the new pressure in the tire is 30.65 psi

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