How many grams of strontium nitrate (Sr(NO3)2) contain 40 grams of oxygen atoms?

Question

05-05-2021
Chemistry

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How many grams of strontium nitrate (Sr(NO3)2) contain 40 grams of oxygen atoms?

Sagot :

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jufsanabriasa jufsanabriasa · Answer 1 · 2021-05-09T20:14:09-04:00

Answer:

88g of Sr(NO3)2 are present

Explanation:

To solve this question we must, as first, find the moles of oxygen. Based on the chemical formula of strontium nitrate, there are 6 atoms of oxygen per mole of strontium nitrate. Thus, we can find the moles of strontium nitrate and its mass as follows:

Moles Oxygen:

40g * (1mol / 16g) = 2.5 moles Oxygen

Moles Strontium nitrate:

2.5 moles Oxygen * (1mol Sr(NO3)2 / 6mol O) = 0.4167 moles Sr(NO3)2

Mass (Molar mass Sr(NO3)2: 211.63g/mol)

0.4167 moles Sr(NO3)2 * (211.63g / mol) =

Sagot :

88g of Sr(NO3)2 are present

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