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Sagot :
Answer:
[tex] \sf \hookrightarrow \: {2x}^{2} + 3x + k = 0 \\ \sf \hookrightarrow \: 2 {(2)}^{2} + 3(2) + k = 0 \\ \sf \hookrightarrow \: 2 \times 4 + 6 + k = 0 \\ \sf \hookrightarrow \: 8 + 6 + k = 0 \\ \sf \hookrightarrow \: 14 + k = 0 \\ \sf \hookrightarrow \: k = - 14[/tex]
Answer:
Step-by-step explanation:
1) substitute x with 2
2*2^2 + 3*2 + k = 0
2) solve the equation
8 + 6 + k = 0
k + 14 = 0
k = -14
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