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Calcium metal is burned completely in oxygen to form 11.2g of calcium oxide. Find the volume of the required oxygen. (Ca = 40, O = 16, 32 of oxygen has 24.4L) *​

Sagot :

dsdrajlin

Answer:

2.44 L

Explanation:

Step 1: Write the balanced equation

2 Ca + O₂ ⇒ 2 CaO

Step 2: Calculate the mass of O₂ required to form 11.2 g of CaO

The molar mass of O₂ is 32 g/mol and in the balanced reaction, there is 1 mole of O₂, that is, 1 mol × 32 g/mol = 32 g.

The molar mass of CaO is 56 g/mol and in the balanced reaction, there are 2 moles of CaO, that is, 2 mol × 56 g/mol = 112 g.

11.2 g CaO × 32 g O₂/112 g CaO = 3.2 g O₂

Step 3: Calculate the volume occupied by 3.2 g of O₂

Under the conditions of the task, 32 g of O₂ occupy 24.4 L.

3.2 g × 24.4 L/32 g = 2.44 L

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