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some patients participated in a clinical trial for a new drug to treat osteoporosis. A patient is selected at random. The probability that the patient had no change in his bone mass density is 7/13, the probability that he had a slight reduction in his bone mass density is 1/k and the probability that he had a significant reduction in his bone mass density is 1/2k. Find the value of k

Sagot :

hamzaahmeds

Answer:

k = 3.9

Step-by-step explanation:

Since the three possible outcomes are given. Therefore, the sum of all the probabilities of the three possible outcomes will be equal to one:

[tex]\frac{7}{13} +\frac{1}{k}+ \frac{1}{2k} = 1 \\\\\frac{1}{k} \frac{1}{2k} =1-\frac{7}{13}\\\\\frac{3}{2k} \frac{5}{13}\\\\2k = \frac{(13)(3)}{5}\\\\k = \frac{39}{(5)(2)}\\[/tex]

k = 3.9

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