bexwhite2610
Answered

Welcome to Westonci.ca, the place where your questions find answers from a community of knowledgeable experts. Discover detailed solutions to your questions from a wide network of experts on our comprehensive Q&A platform. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

At time t = 0 hours, a tank contains 2000 litres of water.
Water leaks from the tank.
At the end of every hour there is x% less water in the tank,
than at the start of the hour.
The volume of water, in litres, in the tank at time t hours is V.
Given that
V = k'V
V. = 1714.75
work out the value of k and the value of x.​

At Time T 0 Hours A Tank Contains 2000 Litres Of WaterWater Leaks From The TankAt The End Of Every Hour There Is X Less Water In The Tankthan At The Start Of Th class=

Sagot :

cairde

Answer:

k= 0.95

x = 5

Step-by-step explanation:

V₀=2000 because at the start (when t=0), there's 2000l in the tank.

V[tex]_{t}[/tex]=[tex]k^{t}[/tex]V₀

V[tex]_{t}[/tex]=2000[tex]k^{t}[/tex]

V₃=1714.75=2000k³

k³=0.857375

k= 0.95

-----

V[tex]_{t}[/tex]=2000[tex]k^{t}[/tex]

V[tex]_{t}[/tex]=2000[tex](0.95^{t})[/tex]

V₁=2000(0.95)=1900

So from V₀ to V₁, the tank loses 100l, which is 5% of it's volume at the start of the hour (100/2000=5%). Therefore x = 5

We appreciate your time. Please come back anytime for the latest information and answers to your questions. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.