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How to find the slope of a line that passes through (8,-2) and the origin​

Sagot :

Answer:

slope = - [tex]\frac{1}{4}[/tex]

Step-by-step explanation:

Calculate the slope m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (0, 0) and (x₂, y₂ ) = (8, - 2)

m = [tex]\frac{-2-0}{8-0}[/tex] = [tex]\frac{-2}{8}[/tex] = - [tex]\frac{1}{4}[/tex]

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