Jaelee04
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help please!!!!!!!!!!!!​

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Sagot :

Dead3ill

Answer:

Q1)

GIVEN :-

  • Diameter = 9m ⇒ Radius (r) = 9/2 = 4.5m
  • Slant height (l) = 13m

TO FIND :-

  • Surface area of the whole figure.

FORMULAES TO KNOW BEFORE SOLVING :-

  • Curved surface area of cone = [tex]\pi rl[/tex] (where r = radius & l = slant height)
  • Curved surface area of hemisphere = [tex]2\pi r^2[/tex] (where r = radius)

PROCEDURE :-

In the figure , the cone is mounted on a hemisphere.

⇒ Radius of cone = Radius of hemisphere = 4.5m

Total surface area of the figure = Curved surface area of both cone & hemisphere.

⇒

  • Curved surface area of cone = [tex]\pi rl = 3.14 \times 4.5 \times 13 = 183.69m^2[/tex] ≈ 183.7m²
  • Curved surface area of hemisphere = [tex]2\pi r^2 = 2 \times 3.14 \times (4.5)^2 = 127.17m^2[/tex] ≈  127.1m²

∴ Total surface area = 183.7 + 127.1 = 310.8m²

Q2)

GIVEN :-

  • Radius (r) = 3km

TO FIND :-

  • Volume of hemisphere
  • Surface area of hemisphere

FORMULAES TO KNOW BEFORE SOLVING :-

  • Volume of hemisphere = [tex]\frac{2}{3} \pi r^3[/tex] (where r = radius)
  • Surface area of hemisphere = [tex]2\pi r^2[/tex] (where r = radius)

PROCEDURE :-

Volume of hemisphere = [tex]\frac{2}{3} \pi r^3 = \frac{2}{3} \times 3.14 \times (3)^3 = 56.52km^3[/tex] ≈ 56.5km³

Surface area of hemisphere = [tex]2\pi r^2 = 2 \times 3.14 \times (3)^2 = 56.52km^2[/tex] ≈ 56.5km²

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