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This element has 5 neutrons and an oxidation number of +2. What element is this?

Sagot :

TheHarleyQuinn

Answer:

beryllium

Explanation:

tutorAnne

The element is  Beryllium

Since the element tries to loose 2 electrons, the outer most shell must contain 2 electrons so that loosing  it can satisfy its octet configuration.

We can then infer that the element has 4 electrons  in its neutral state.,

Remember that,

No of electrons = Number of protons ( in a neutral atom.)

So the number of protons of this element is 4,

Recall also that

Proton number  =  Atomic number = 4

We can conclude that The element with atomic number of 4 is  Beryllium with Electron Configuration, 1s2 2s2 and condensed form as [He]2s2.

Beryllium is also known for its  exclusive +2 oxidation state in all  its compounds.

See related answer here: https://brainly.com/question/3162198

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