Westonci.ca is your trusted source for accurate answers to all your questions. Join our community and start learning today! Explore thousands of questions and answers from knowledgeable experts in various fields on our Q&A platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

Question 2 (2 points)
Find the indicated limit, if it exists. (2 points)

1) 0
2) 8
3) 3
4) The limit does not exist.


Question 2 2 Points Find The Indicated Limit If It Exists 2 Points 1 0 2 8 3 3 4 The Limit Does Not Exist class=

Sagot :

Space

Answer:

4) The limit does not exist.

General Formulas and Concepts:

Calculus

Limits

  • Right-Side Limit:                                                                                             [tex]\displaystyle \lim_{x \to c^+} f(x)[/tex]
  • Left-Side Limit:                                                                                               [tex]\displaystyle \lim_{x \to c^-} f(x)[/tex]

Limit Rule [Variable Direct Substitution]:                                                             [tex]\displaystyle \lim_{x \to c} x = c[/tex]

Step-by-step explanation:

*Note:

For a limit to exist, the right-side and left-side limits must be equal to each other.

Step 1: Define

Identify

[tex]\displaystyle f(x) = \left\{\begin{array}{ccc}5 - x ,\ x < 5\\8 ,\ x = 5\\x + 3 ,\ x > 5\end{array}[/tex]

Step 2: Find Left-Side Limit

  1. Substitute in function [Left-Side Limit]:                                                       [tex]\displaystyle \lim_{x \to 5^-} 5 - x[/tex]
  2. Evaluate limit [Limit Rule - Variable Direct Substitution]:                          [tex]\displaystyle \lim_{x \to 5^-} 5 - x = 5- 5 = 0[/tex]

Step 2: Find Left-Side Limit

  1. Substitute in function [Right-Side Limit]:                                                     [tex]\displaystyle \lim_{x \to 5^+} x + 3[/tex]
  2. Evaluate limit [Limit Rule - Variable Direct Substitution]:                           [tex]\displaystyle \lim_{x \to 5^+} x + 3 = 5 + 3 = 8[/tex]

∴ since  [tex]\displaystyle \lim_{x \to c^+} f(x) \neq \lim_{x \to c^-} f(x)[/tex]  ,  [tex]\displaystyle \lim_{x \to 5} f(x) = \text{DNE}[/tex]

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Limits