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Find the value of x in the triangle shown below.

Choose 1 answer:

A- x=[tex]\sqrt{80}[/tex]

B- x=[tex]\sqrt{48}[/tex]

C- x=[tex]\sqrt{32}[/tex]

D- x=[tex]\sqrt{12}[/tex]

Find The Value Of X In The Triangle Shown Below Choose 1 Answer A Xtexsqrt80tex B Xtexsqrt48tex C Xtexsqrt32tex D Xtexsqrt12tex class=

Sagot :

Answer:

Option A, x = [tex]\sqrt{80}[/tex]

Step-by-step explanation:

Pythagorean Theorem states: A² + B² = C² ( A and B are the legs, C is always the hypotenuse)

⇒ A² + B² = C²

⇒ 4² + 8² = x²

⇒ 16 + 64 = x²

⇒ 80 = x²

⇒ [tex]\sqrt{80} = \sqrt{x^{2} }[/tex]

⇒ [tex]\sqrt{80} = x[/tex]

Hope this helps!

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