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Find the point that partitions segment AB in a 2: 1 ratio.


Please don't give me a link to a file, because it doesn't work for me.

Find The Point That Partitions Segment AB In A 2 1 Ratio Please Dont Give Me A Link To A File Because It Doesnt Work For Me class=

Sagot :

Answer is 7-8 because this means you need to line the graph and put them together than you will find the answer. 7-8.
ashishdwivedilVT

The point that partitions segment AB in a 2: 1 ratio is point (5,19/3).

Suppose the point that partitions segment AB in a 2: 1 ratio is point (x,y)

What is the internal division formula?

The internal division formula for a line segment is given by:

[tex]x=\frac{m_1x_2+m_2x_1}{m_1+m_2}[/tex]

[tex]y=\frac{m_1y_2+m_2y_1}{m_1+m_2}[/tex]

Where (x₁,y₁) and (x₂,y₂) are endpoints of the line segment.

Coordinates of points A≡(1,3)

Coordinates of points B≡(7,8)

[tex]x=\frac{2*7+1*1}{1+2}[/tex]

[tex]x=5[/tex]

Similarly, [tex]y=\frac{19}{3}[/tex]

So (x,y)≡(5,19/3)

Hence, the point that partitions segment AB in a 2: 1 ratio is point (5,19/3).

To get more about straight lines visit:

https://brainly.com/question/13284474

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