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Sagot :
Answer: [tex]75\ ft^2[/tex]
Step-by-step explanation:
Given
The dimension of playspace is [tex]10\ ft\times 12\ ft[/tex]
If the length and width is increased by 3 ft
New length is [tex]13\ ft[/tex]
New width is [tex]15\ ft[/tex]
So, the dimension becomes [tex]13\ ft\times 15\ ft[/tex]
The difference between the areas of the playspace is
[tex]\Rightarrow 13\times 15-10\times 12\\\Rightarrow 195-120=75\ ft^2[/tex]
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