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The cells of a tomato contain mostly an aqueous solution of sugar and other substances. If a typical tomato freezes at -2.5 °C, what is the molality of the sugar in solution? (Hint: sugar is a covalent compound, it does not dissociate in water)

Sagot :

maacastrobr

Answer:

1.35 m

Explanation:

We can solve this problem by using the freezing point depression formula:

  • ΔT = Kf * m * i

Where:

  • ΔT is the temperature difference between the freezing point of the pure solvent (water) and the solution. In this case it is (0 °C - -2.5 °C = 2.5 °C).
  • Kf is the cryoscopic constant, for water it is 1.853  °C*kg/mol.
  • m is the molality.
  • i is the van't Hoff factor, as sugar does not dissociate in water, it has a value of 1.

We input the data:

  • 2.5 °C = 1.853 °C*kg/mol * m * 1

And solve for m:

  • m = 1.35 m
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