Answered

Looking for reliable answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Explore thousands of questions and answers from knowledgeable experts in various fields on our Q&A platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

Some red, white, and blue candies were placed in a bowl. Some contain nute,
and some do not suppose one of the candies were chosen randomly from all
the candles in the bowl. According to the table below, if the candy le blue,
what is the probability that it does not contain any nute?
Red White Blue
Nuta 10 20 20
No nutel 10 10 30
A. 40%
B. 60%
C. 10%
D, 20%

Some Red White And Blue Candies Were Placed In A Bowl Some Contain Nute And Some Do Not Suppose One Of The Candies Were Chosen Randomly From All The Candles In class=

Sagot :

Answer:

Answer:

Option B: 60%

Step-by-step explanation:

The number of blue candies with nuts = 20

The number of blue candies without nuts = 30

The total number of blue candies = 20 + 30 = 50

As the chosen candy is blue, the probability that is does not contain any nuts will be = (The number of blue candies without nuts)/(Total number of blue candies)

So, the probability = 30/50 = 0.6 *100% = 60%
B.60 percent is the correct answer
We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.