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The box for a computer game measures 19 cm by 14 cm by 1.5 cm. What is the total amount of plastic wrapping needed to cover the entire box if an extra 66 square cm are needed to allow for overlapping at the edges?

Sagot :

Answer:

697 cm²

Step-by-step explanation:

The box for a computer game measures 19 cm by 14 cm by 1.5 cm.

The amount of plastic wrapping needed to cover the entire box is calculated using the formula for the Surface Area of a rectangular prism

The formula is given as:

A=2(wl +hl + hw)

W = Width = 19cm

L = Length = 14 cm

H = Height = 1.5 cm

2 × (19 × 14 + 1.5 × 14 + 1.5 × 19)

= 631 cm²

Therefore, the total amount of plastic wrapping needed to cover the entire box if an extra 66 square cm are needed to allow for overlapping at the edges is calculated as:

631 cm² + 66 cm²

= 697 cm²

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