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Sagot :
Answer:
.496 M .
Explanation:
15.5 mL of .8 M NaOH will contain .0155 x .8 moles of NaOH
moles of NaOH = .0124 moles
For neutralization, moles contained by 25 mL of HCl = .0124
Hence molarity of HCl = .0124 / .025
= .496 M .
0.496 M is the molarity of an HCl solution if 25.0 mL of the solution is neutralized by 15.5 mL of 0.800 M NaOH.
What is molarity?
Molarity (M) is the amount of a substance in a certain volume of solution. Molarity is defined as the moles of a solute per litres of a solution. Molarity is also known as the molar concentration of a solution.
Molarity = [tex]\frac{Moles \;solute}{Volume of solution in litre}[/tex]
15.5 mL of 0.8 M NaOH will contain 0.0155 x 0.8 moles of NaOH
Moles of NaOH = 0.0124 moles
For neutralization, moles contained by 25 mL of HCl = 0.0124
Hence molarity of HCl = [tex]\frac{0.0124}{0.025}[/tex]
= 0.496 M .
Hence, 0.496 M is the molarity of an HCl solution if 25.0 mL of the solution is neutralized by 15.5 mL of 0.800 M NaOH.
Learn more about the molarity here:
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