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Sagot :
Answer:
Let AB be the height of electric tower and BC be its base.
it forms a right angled triangle
so
base=BC=50ft
hypotenuse =AC=?
perpendicular=AB=200ft
by using Pythagoras law
h²=p²+b²
AC²=200²+50²
AC=√42500
AC=206.15ft
206.15ft is the length of wire.

Using Pythagorean theorem
[tex]\\ \sf\longmapsto AC^2=200^2+50^2[/tex]
[tex]\\ \sf\longmapsto AC^2=40000+2500[/tex]
[tex]\\ \sf\longmapsto AC^2=42500[/tex]
[tex]\\ \sf\longmapsto AC=206.15ft[/tex]

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