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Sagot :
Answer:
after 11.07secs
Step-by-step explanation:
Given the height of an object modeled by the equation
H = 16T² - 1960
The height of the object on the surface of water is zero, hence H = 0
Substitute
0 =16T² - 1960
Swap
16T² - 1960 = 0
16T² = 1960
T² = 1960/16
T² = 122.5
T = 11.07
Hence the rock will hit the surface of the water after 11.07secs
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