Answered

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2x²-5x+2=0 solve for x​

Sagot :

[tex]{ \huge {\underline {\underline {\mathfrak {\purple{Answer}}}}}}[/tex]

[tex] \longmapsto{2 {x}^{2} - 5x + 2}[/tex]

[tex] \longmapsto{2 {x}^{2} - 4x - x + 2}[/tex]

[tex]\longmapsto{2x(x - 2) - 1(x - 2)}[/tex]

[tex]\longmapsto{(2x - 1)(x - 2)}[/tex]

[tex] \boxed{ \huge x = \huge\dfrac{1}{2} \: or \: 2}[/tex]

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