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Sagot :
Answer:
La presión que los patinadores ejercen sobre el hielo es 7,848,000 Pa
Explanation:
Los parámetros dados de los patinadores en la pala son;
La longitud de la hoja en el patín, l = 30 cm = 0.03 m
El espesor de la hoja, t = 5 mm = 0,005 m
El peso de las dos personas, m = 120 kg
Suponiendo que la sección transversal de la cuchilla sobre el hielo es rectangular, tenemos;
A = l × t
∴ A = 0,03 m × 0,005 m = 0,00015 m²
La fuerza de peso de los dos patinadores, W = m × g
Dónde;
g = La aceleración debida a la gravedad ≈ 9,81 m / s²
m = La masa de los dos patinadores = 120 kg
∴ W = 120 kg × 9,81 m / s² = 1,177,2 N
Presión, P = Fuerza, F/(Área, A)
∴ P = (1.177,2 N) / (0.00015 m²)= 7,848,000 Pascals
La presión que los patinadores ejercen sobre el hielo., P = 7,848,000 Pascals
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