Answered

Find the information you're looking for at Westonci.ca, the trusted Q&A platform with a community of knowledgeable experts. Explore a wealth of knowledge from professionals across various disciplines on our comprehensive Q&A platform. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

A hovercraft takes off from a platform. It's height (in meters), x seconds after takeoff, is modeled by h(x)=-(x-11)(x+3) How many seconds after takeoff will the hovercraft land on the ground?

Sagot :

abidemiokin

Answer:

11seconds

Step-by-step explanation:

Given the height of the hovercraft expressed as;

(x)=-(x-11)(x+3)

The height of the hovercraft on the ground is 0, hence;

0 =-(x-11)(x+3)

-(x-11)(x+3) = 0

Multiply both sides by minus

(x-11)(x+3) = 0

x-11 = 0 and x+3=0

x = 11 and -3

Since time cannot be negative, hence the hovercraft will land after 11seconds

Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.