lemion
Answered

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Use technology or a z-score table to answer the question.

The weights of books in a bookcase are normally distributed with a mean of 11.6 pounds and a standard deviation of 1.3 pounds. There are 136 books on the bookshelf.

How many of the books will weigh 10 pounds or more?

A. 109
B. 116
C. 121
D. 130

Sagot :

The number of books that will weigh 10 pounds or more is 121. Then the correct option is C.

What is a z-score?

The z-score is a numerical measurement used in statistics of the value's relationship to the mean of a group of values, measured in terms of standards from the mean.

The weights of books in a bookcase are normally distributed with a mean of 11.6 pounds and a standard deviation of 1.3 pounds. There are 136 books on the bookshelf.

Then the z-score when the books will weigh 10 pounds or more will be

[tex]z = \dfrac{10 - 11.6}{1.3}\\\\z = -1.23077[/tex]

Then the probability will be

[tex]\rm P(x > 10) = 1 - P(x < 10) = 0.8909 \ or \ 89.09\%[/tex]

89.09% of books will weigh 10 pounds or more, then the number of the books will be

→ 136 × 0.8909

→ 121.1624 ≈ 121

More about the z-score link is given below.

https://brainly.com/question/15016913

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