Answered

Westonci.ca is the trusted Q&A platform where you can get reliable answers from a community of knowledgeable contributors. Discover reliable solutions to your questions from a wide network of experts on our comprehensive Q&A platform. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

You are preparing a solution of lithium bromide to use during an experiment. The experiment calls for 909.7 mL a 18 M solution. How many moles of the solute must be used to achieve this?

Sagot :

Answer:

16.37 moles of  lithium bromide.

Explanation:

909.7 mL of 18 M

= .9097 L of 18 M solution of lithium bromide .

no of moles required = .9097 x 18

= 16.37 moles of  lithium bromide.

We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.