At Westonci.ca, we make it easy to get the answers you need from a community of informed and experienced contributors. Discover a wealth of knowledge from professionals across various disciplines on our user-friendly Q&A platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.
Sagot :
Answer:
[tex]\sum \limits ^{n}_{k=1} 4 \Big [ 1 + \dfrac{3k}{n} \Big] \Big [ \dfrac{3}{n} \Big ][/tex]
Step-by-step explanation:
Given the function:
f(x) = 4x; we are to determine the expression given the Reimman sum formula for the given function f(x) = 4x over the interval [1,4]
Since;
[tex]\Delta x = \dfrac{4-1}{x} = \dfrac{3}{x} \\ \\ x_i = a+ \Delta x_i[/tex]
where;
a = 1 and Δ = 4
∴
[tex]x_i = 1+ \dfrac{3}{x}i[/tex]
For i = k
[tex]x_k = 1+ \dfrac{3}{x}k[/tex]
However;
[tex]y(x_i) = 4x \\ \\ y(x_i) = 4(1 +\dfrac{3i}{x})[/tex]
Thus, the formula for the Reinmann sum is:
[tex]\sum \limits ^{n}_{k=1} \Big [ 4 \Big [ 1 + \dfrac{3i}{x} \Big] \Big ] \Delta x \\ \\ \\ \sum \limits ^{n}_{k=1} \Big [ 4 \Big [ 1 + \dfrac{3k}{x} \Big] \Big ] \dfrac{3}{x}[/tex]
Since we are taking the limit as n → ∞
[tex]\sum \limits ^{n}_{k=1} 4 \Big [ 1 + \dfrac{3k}{n} \Big] \Big [ \dfrac{3}{n} \Big ][/tex]
Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.