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A jar contains 18 apple lollipops, 7 strawberry lollipops, and 10 grape lollipops. Irvin randomly selects a lollipop, gives it to his brother, and then randomly selects another lollipop for himself.

What is the probability that Irvin selected a grape lollipop for his brother and an apple lollipop for himself?

Write your answer as a percent. Round to the nearest tenth of a percent.

Sagot :

First  choice is  "1 of 10 grape lollipops from 35 lollipops"  
The probablity is 10/35 = 2/7 
Second choice is  "1 of 18 apple lollipops from 34 lollipops"  
So probablity is 18/34 = 9/17 
Between this is  AND so you have to these probablities multiply:
P(A) = 2/7 * 9/17 = 18/119 
P(A) = 18/119 * 100% = 1800/119 %
It is approximaly 15,1 %. 
44popcorn44

Answer:

15.1%

Step-by-step explanation:

So we need to find the probabilities and multiple them to get our answer. Our first probability is out of 35 lollipops total how likely is it that Irvin picks a grape.

10/35

But then Irvin gets another lollipop for himself. What is the likelihood he will get a apple lollipop out of the 34 (we removed one to give to his brother).

18/34.

So our final equation is

10/35 x 18/34=0.151 (rounded)

15.1%

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