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Circuit Training If sin0 =1 and 0 <0< π find 0.

Sagot :

Answer:

[tex]\theta = \frac{\pi}{2}[/tex]

Step-by-step explanation:

Given

[tex]\sin(\theta) = 1[/tex]

[tex]0 < \theta < \pi[/tex]

Required

Find [tex]\theta[/tex]

[tex]0 < \theta < \pi[/tex] implies that [tex]\theta[/tex] is between 0 and 180 degrees

[tex]\sin(\theta) = 1[/tex]

Take arcsin of both sides

[tex]\theta = sin^{-1}(1)[/tex]

This gives:

[tex]\theta = \frac{\pi}{2}[/tex]

Convert to degrees

[tex]\theta = \frac{\pi}{2} * \frac{180}{\pi}[/tex]

[tex]\theta = 90[/tex]

We have:

[tex]0 < \theta < \pi[/tex] or [tex]0 < \theta < 180[/tex]

To get other values of [tex]\theta[/tex]

We use:

[tex]\sin(\theta) = \sin(180 - \theta)[/tex]

Substitute: [tex]\theta = 90[/tex]

[tex]\sin(90) = \sin(180 - 90)[/tex]

[tex]\sin(90) = \sin(90)[/tex]

This means that there are no other values of [tex]\theta[/tex] in the given range