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What is the simplest form x^2-16/x^2+5x+4fied form of

Sagot :

sqdancefan

9514 1404 393

Answer:

  (x -4)(x +1)

Step-by-step explanation:

  [tex]\dfrac{x^2-16}{x^2+5x+4}=\dfrac{(x+4)(x-4)}{(x+4)(x+1)}=\boxed{\dfrac{x-4}{x+1}}\qquad x\ne-4[/tex]

The simplified form comes with a domain restriction corresponding to the hole in the function where the original denominator is zero.

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