Answered

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A sucrose solution is prepared by dissolving 18.50 g of sucrose C12H22011, in 150 g
of water. What is the molality of the sucrose solution? [Molar mass (g/mol):
C12H22011 = 342.3 and H20 = 18.02]
O a.
0.56m
O b. 0.36m
O c.
0.17m
O d. 0.0228m

Sagot :

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Answer:

B. 0.36

Explanation:

18.5/342.3 = .054 mols of Surcrose

150g of water = .15kg

molality = mols/kg of solvent

.054/.15 = 0.36 molalality

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