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Sagot :
Answer:
5.8 feet
Step-by-step explanation:
this problem uses a 30-60-90° triangle
the ratio of sides in a 30-60-90° triangle, respectively, are 1 : [tex]\sqrt{3}[/tex] : 2
let 'h' = height of ramp
we can use this proportion, then cross-multiply:
10/h = [tex]\sqrt{3}[/tex]/1
[tex]\sqrt{3}[/tex]h = 10
h = 10/[tex]\sqrt{3}[/tex]
after rationalizing the denominator we get:
(10[tex]\sqrt{3}[/tex] ) ÷ 3 which is approximately 5.8 feet
Using the trigonometric ratio, the height of the ramp is 5.77 feet.
Length of bicycle ramp = 10 feet
Angle with the ground = 30°
What is the sine of an angle?
The tangent of an angle is the ratio of the opposite side to the adjacent of the triangle.
Suppose the height of the ramp is h.
So, [tex]tan30=\frac{h}{10}[/tex]
[tex]h=10tan30[/tex]
[tex]h=\frac{10}{\sqrt{3} }[/tex]
[tex]h=5.77[/tex] feet.
So, the height of the ramp is 5.77 feet.
Hence, using the trigonometric ratio, the height of the ramp is 5.77 feet.
To get more about the trigonometric ratios visit:
https://brainly.com/question/24349828
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