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An identification code is to consist of 3 letters followed by 3 digits. Determine the following
a) How many different codes are possible if repetition is not permitted?

I got 11,232,000, but I'm pretty sure that's wrong.

Sagot :

Answer:

3 letters can be arranged in 26*25*24 = 15600 ways

3 digits can be arranged in 10 * 9 * 8 = 720 ways

So the total number is 15600 * 720 = 11,232,000

So I agree with the number that you obtained