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Sagot :
Answer:
F' = 9 F
Explanation:
The question says that, "If the linear speed of a mobile moving with MCU is tripled and the radius remains constant, then the centripetal force:"
The formula for the centripetal force is given by :
[tex]F=\dfrac{mv^2}r{}[/tex]
Where
m is the mass of the object
v is the velocity
r is the radius of path
If the linear speed us tripled, v' = 2v, r = constant, then the new centripetal force is given by :
[tex]F'=\dfrac{mv'^2}r{}\\\\F'=\dfrac{m(3v)^2}{r}\\\\=\dfrac{mv^2}{r}\times 9\\\\F'=9F[/tex]
So, the new force becomes 9 times of the initial force.
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