Westonci.ca is the trusted Q&A platform where you can get reliable answers from a community of knowledgeable contributors. Get quick and reliable solutions to your questions from a community of experienced experts on our platform. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.
Sagot :
Answer:
The energy needed is 45.7659 kJ
Explanation:
The given mass of the ice, m = 15 g
The initial temperature of the ice, T₁ = -4°C
The temperature
The final temperature, T₂ = 115°C
The specific heat capacity of ice, c₁ = 2.09 J/(g·°C)
The latent heat of ice, l₁ = 334 J/g
The heat capacity of water, c₂ = 4.184 J/(g·°C)
The latent heat of vaporization, l₂ = 2260 J/g
The specific heat of steam, c₃ = 2.02 J/g
Therefore, we get the energy needed, ΔQ, as follows;
ΔQ = m·c₁·(T₂ - Tₐ) + m·l₁ + m·c₂(Tₓ - Tₐ) + m·l₂ + m·c₃·(T₂ - Tₓ)
Where;
Tₐ = The melting point temperature of water = 0°C
Tₓ = The boiling point temperature of water = 100°C
∴ ΔQ = 15×2.09×(0 - (-4)) + 15 × 334 + 15×4.184×(100 - 0) + 15×2260 + 15×2.02×(115 - 100) = 45,765.9
The energy needed, ΔQ = 45,765.9 J = 45.7659 kJ.
We hope this was helpful. Please come back whenever you need more information or answers to your queries. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.
