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determine the value of x in the equation below. (3a3)x=27a9

Sagot :

Answer:

[tex]x = 9 {a}^{6} [/tex]

Step-by-step explanation:

[tex] = > {3a}^{3} x = 27 {a}^{9} [/tex]

[tex] = > {a}^{3} x = \frac{27a^{9} }{3} [/tex]

[tex] = > {a}^{3} x = 9a ^{9} [/tex]

[tex] = > x = \frac{9 {a}^{9} }{ {a}^{3} } [/tex]

[tex] = > x = 9a^{9 - 3} [/tex]

[tex] = > x = 9 {a}^{6} [/tex]

hence, the answer is x = 9a⁶.

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