Answered

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Prove: An odd times an odd equals an
odd.
(2m + 1)(2n + 1) = [ ? ]mn + ]m +[ ]n + [ ]
= 2([ ]mn + m + 1 + 1
= odd

Prove An Odd Times An Odd Equals An Odd 2m 12n 1 Mn M N 2 Mn M 1 1 Odd class=

Sagot :

Answer:

See below

Step-by-step explanation:

(2m+1)(2n+1)

=4mn+2m+2n+1

=2(2mn+m+n)+1

=odd

An odd time and an odd equals an odd has been proved below.

What is an odd number?

An odd number is a number if we divide by 2, leave a remainder as 1.

⇒The sum of two odd numbers is always even(which can be divided by 2 ).

⇒The product of two or more odd numbers is always odd.

The sum of the even number and odd numbers is always an odd number, while the sum of an odd number of odd numbers is always even. For example, the sum of the given odd numbers 7, 3, 1, and 5 is 16, while the sum of given odd numbers 7, 1, 9, and 13 is 30.

Given that the expression

⇒ (2m + 1)(2n + 1)

⇒ 4mn+2m+2n+1

⇒ 2(2mn+m+n)+1

hence, it comes out of 2 ×something which will always even +1 which gives an odd number.

For more information about odd number

https://brainly.com/question/240064

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