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Sagot :

Let the three consecutive odd numbers be x,x+2,x+4.
Given, their sum =219

Therefore, x+x+2+x+4=219
⇒3x+6=219
Subtract 6 from both the sides,
⇒3x+6−6=219−6

⇒3x=213
⇒x=71
The other numbers are x+2=71+2=73 and x+4=71+4=75.

Therefore, threee odd numbers are 71,73 and 75.
71 and 73 and 75 odd numbers
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