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Balance it by oxidation number method:KMnO4+H2SO4+H2S---->K2SO4+MnSO4+H2S +S​

Sagot :

msm555

Answer:

Answer:

step 1:balance skeleton equation the chemical equation:

KMnO4+H2SO4+H2S➔K2SO4+MnSO4+H2O+S

step 2: identity undergoing oxidation or reduction

here

KMnO4➔MnSO4

Mn is reduced from 7 to 2 in oxidation no.

H2S➔S

S is oxidized from -2 to 0 in oxidation no

Step 3: calculate change in oxidation no.

change in oxidation no

in Mn=2-7=-5=5

in

S=0--2=2

Step 4: Balance it by doing crisscrossed multiplication

we get;

2KMnO4+H2SO4+5H2S➔K2SO4+2MnSO4+H20+5S

step 6:Balance other atoms except H & O

2KMnO4+3H2SO4+5H2S➔K2SO4+2MnSO4+H20+5S

finally: balance H

2KMnO4+3H2SO4+5H2S➔K2SO4+2MnSO4+8H20+5S

Step-by-step explanation:

hope it is helpful to you

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