Answered

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Function f (x) = 25x/x + 3 has a discontinuity at x = –3. What are Limit of f (x) as x approaches negative 3 minus and Limit of f (x) as x approaches negative 3 plus?

Sagot :

whitneytr12

Answer:

x approaches negative 3 to the right: [tex]lim_{x\to -3^{+}}=-\infty[/tex]

x approaches negative 3 to the left: [tex]lim_{x\to -3^{-}}=\infty[/tex]

Step-by-step explanation:

The function we have is:

[tex]f(x)=\frac{25x}{x+3}[/tex]

We have an asymptote at x = -3.

The limit of the function when x approaches negative 3 to the right will be:

[tex]lim_{x\to -3^{+}}=\frac{25x}{(-3)+3}=-\infty[/tex]

It is because the function is decreasing from right to left.

And the limit of the function when x approaches negative 3 to the left will be:

[tex]lim_{x\to -3^{-}}=\frac{25x}{(-3)+3}=\infty[/tex]

It is because the function is decreasing from left to right.

I hope it helps you!

Answer: C

Step-by-step explanation:

Edge

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